#### Answer

$f(x)=3 (x+3)(x-1)(x-4)$

#### Work Step by Step

Let us consider that $a$ is a zero of a function with multiplicity $b$. Then this factor of the function can be expressed as: $(x-a)^b$.
Therefore, we can write the equation of the function as:
$f(x)=k (x+3)(x-1)(x-4)~~~~(1)$
Since, $(0,36)$ lies on the graph, we have:
$k(3)(-1)(-4) =36\\12k =36 \\k=3$
Thus, equation (1) becomes:
$f(x)=3 (x+3)(x-1)(x-4)$